Hope you’re doing well.

Our today’s topic is

Brackets :How to use in equation solution

Here I’m going to explain

###
**what If one don’t place brackets at right positions while solving any equation consisting one or more Functions?**

**what changes comes for not placing brackets?**

**what happens if brackets placed at right place?**

**what If one don’t place brackets at right positions while solving any equation consisting one or more Functions?****what changes comes for not placing brackets?****what happens if brackets placed at right place?**So without wasting time I’m starting,

suppose an equation is given

5x+ 4x =9x

but

5x+ -4x =9x,-9x , 1x, -1x

this creates confusion to some learners that from which function the equation will be operated,

so this should be

5x+(-4x) = 5x -4x = 1x or x

similarly,

22+ 6 -8 ×-7 …..?????

this should be written correctly first i.e.

22 + 6 – 8 × (-7)

apply Bodmas rule

22 + 6 – -56

again it should be written correctly

22 + 6 – (-56)

22 + 6 + 56

84.

and in algebra if the equation is,

3y + 5 × -x – 6÷ -3 …😒😓

quite confusion ha…!!!

OK, see below,

3y + 5× (-x) -6 ÷(-3)

3y -5x + 6/3

ans .

3y – 5x + 2.

must read tutorials:

again if

**Q. Divide 6x + -4x – 3y by 3.**

if we write the above statement like

6x +(-4x) -3y ÷3

then it is totally wrong as instead of the equation only last term i.e. -3y is seems to be divided by 3,

so, we should place suitable **Brackets**

like

[ 6x +(-4x) -3y ] / 3

now this is explaining itself that the whole equation is divided by 3.

[ 6x -4x -3y] /3

[ 2x -3y ] /3

this is it.

I hope this tutorial of importance of brackets in math, remain helpful for you.

please Share and comment.