don’t stressed…

I said with same topic but the advance level of the Algebraic fractions….

YES..!!

Algebraic Fractions

#### Solution of algebraic fractions having two or more terms and having unknown variables and also those equations which are containing TRIGONOMETRIC functions.

### Solutions of Equations based upon two variables :-

(original expression) | |

=2x+3⋅x−1x−1−3xx−1⋅x+3x+3 =2x+3⋅x−1x−1−3xx−1⋅x+3x+3 |
rather we can solve this step with an easy method by multiplying denominators to the numerator and multiplying denominators to each other i.e. |

=2(x−1)−3x(x+3)(x+3)(x−1) =2(x−1)−3x(x+3)(x+3)(x−1) | (keep the denominator the same; add the numerators) |

=2x−2−3×2−9x(x+3)(x−1) =2x−2−3×2−9x(x+3)(x−1) | (multiply out the numerator) |

=−3×2−7x−2(x+3)(x−1) |

so, you can analyse how the fraction solution becomes easier without finding out the LCM of denominators.

see some more examples having exponents as well… but do remember we will apply BODMAS RULE first in the Solutions…

for brief explanation check this picture based solution

### what if the equation is given with two variables:-

x/2 + y/3

answer is

(3x + 2y)/ 6

one more check this out-

**Solution:**

firstly in above solution the denominators made similar through Identity

*a² – b² = (a+b)(a-b)*

then after there is no need to proceed the Solutions like above explained, so it is concluded that if the denominators are similar Solutions can be proceed from numerators themselves with respect to their signs.

### What if there is three fraction terms are given:-

1×2−3x+2+1×2−5x+6+1×2−4x+x² – 4x +3

**Solution:**

here is also made the denominators similar and processed similarly.

Hope you have grasp the concepts regarding solving algebraic fractions. If you have any doubt then please share that in comment box, I’ll be pleased to clear those doubts and also do subscribe for our new post direct to your Mail ID.

Thanks,

Happy learning…